Hi,
A little question how to get the name of sample as in the screenshot i want to get “wren”.
chemin_echantillons ="D:/audio/samples/birds"
sample chemin_echantillons
Thanks
Hi,
A little question how to get the name of sample as in the screenshot i want to get “wren”.
chemin_echantillons ="D:/audio/samples/birds"
sample chemin_echantillons
Thanks
Hi there,
Well i suggest this code to achieve my first goal.
yourSamplesPath ="D:/audio/mesSamples/Jazz-02"
# ros = ring_of_samples
# filter samples only with loop into the name
ros = sample_paths yourSamplesPath, ""
## function to get only the name of the fileName to populate a friendly list by example
define :getName do |fullPath|
fileNameWithExtension = fullPath.split("/")[-1] # to get the file name with the extension
return fileName = fileNameWithExtension.split(".")[0] # to get the name without the extension
end
puts "---------------------------------"
puts "Number of samples : " + ros.length.to_s
puts "--------- Name of samples ------ "
k=0
while k<ros.length
puts getName((ros)[k])
# by example to be sent by osc_send to a list
# to prepare the playing
load_sample (ros)[k]
k = k+1
end
puts "--- Let's play all the samples --------"
May it helps.
Cheers